((2x-1)/(x^2-2x-3))-((x-5)/(x^2+4x+3))=x/(x^2-9)

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Solution for ((2x-1)/(x^2-2x-3))-((x-5)/(x^2+4x+3))=x/(x^2-9) equation: 



((2x-1)/(x^2-2x-3))-((x-5)/(x^2+4x+3))=x/(x^2-9)

We move all terms to the left:

((2x-1)/(x^2-2x-3))-((x-5)/(x^2+4x+3))-(x/(x^2-9))=0



Domain of the equation: (x^2-2x-3))!=0

x∈R





Domain of the equation: (x^2+4x+3))!=0

x∈R





Domain of the equation: (x^2-9))!=0

x∈R



We calculate fractions


(((2x-1)*(x^2+4x+3))*x^2)/(4x+(x^2-2x-3))*(x^2+3))*(x^2-9)))+(-((x-5)*(x^2-2x-3))*x^2)/(4x+(x^2-2x-3))*(x^2+3))*(x^2-9)))+(-(4x+x*(x^2-2x-3))*x^2)/(4x+(x^2-2x-3))*(x^2+3))*(x^2-9)))=0

We can not solve this equation

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